**Determine the location of the 30N Force.**Depress mouse to view answer. Answer: x = 85.83 cm ccw = cw (35 N)(35 cm)=(30 N)(X) 1225 N*cm = 30 N*x x = 40.83 cm to the right of the fulcrum (or) x = 85.83 cm **Consider the system below for question #2:****Determine the Force at 40 cm.**Depress mouse to view answer. Answer: x = 25.0 N (25 N)(50 cm) + (X)(10 cm) = (30 N)(50 cm) 1250 N*cm + 10 cm*x = 1500 N*cm 10 cm*x = 250 N*cm x = 25.0 N **Consider the system below for question #3:****Determine the Force at 80 cm.**Depress mouse to view answer. Answer: x = 3.5 N Force (center of mass meter stick) = 0.50 N @ 50 cm (5 N)(35 cm) + (4 N)(10 cm) - (2 N)(45 cm) = (0.50 N)(5 cm) + (x)(35 cm) or (5 N)(35 cm) + (4 N)(10 cm) = (2 N)(45 cm) + (0.50 N)(5 cm) + (x)(35 cm) 175 N*cm + 40 N*cm = 90 N*cm + 2.5 N*cm + 35 cm*x 215 N*cm = 92.5 N*cm + 35 cm*x 122.5 N*cm = 35 cm*x x = 3.5 N **Consider the system below for question #4:****Determine the position of the fulcrum to put the system into equilibrium**

**Consider the system below for question #5:****If A = 3N, determine the weight of B,C,D,E, and F**

(If you can do this, you understand torque)